That's a nice idea, you could change the first babe (in attack order) by the most powerful moe to counter the one that chose their helper (they will choose a sexy as helper) but this deck is really unsuited for attack ...
In a fight against a full moe it will be something like that :
With sexy x3 and babe x2 :
-Your 1st sexy lose -> helper win for you (if it's a babe)
-Your 2nd and 3rd sexy lose
-1st babe win for you, his helper will fight if it's a sexy you lose, if it's a babe it depend and if it's a moe you win.
-2nd babe wins
You can only win if he doesn't choose a sexy as helper.
sexy x3, moe x1 and babe x1 case (I assume the moe you use is the best one) :
-Your 1st sexy lose -> helper win for you (if it's a babe)
-Your 2nd and 3rd sexy lose
-Your moe wins if his moe isn't also the best one, his assist come -> win if it's a sexy, moe win if it's not the best once again, and of course lose if it's a babe
-Your babe wins
I don't say it's a better defensive deck but it can win against people which have a perfect attack deck.
PerPero ID : 248244
LoV, Aigis & Angelic saga : KaAnor